Probability between z = 0 and z = 3.01 is given by
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987
The # in decimal form would be A
You can also do the division with remainders to find the answer:
195 ÷ 96 = 2,041666666666667
So you can clearly see that there are more than two but less than three 96s in 195. So multiply 96 by 2 and then substract the result from 195 to find the remainder:
96 * 2 = 192
195 - 192 = 3
It means that in 195 there will fit two 96s with a remainder of 3.
We can also write it as two 96s and 3/96, what can be further simplified to two 96s and 1/32.
He can make 3 loaves of bread, with a remainder of 1/4 cup of butter.
