D. Subtract 2 from the number of sides and multiply the difference by 180
Answer:
The solutions are 
Step-by-step explanation:
we have

Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares

square root both sides


Answer:
Step-by-step explanation:
Given that
Area of a circle 
Circumference of the circle 
Let us re-write the equation of area of circle:


Multiplying and dividing with 2:

Hence, <em>A</em> in terms of <em>C</em> can be represented as:
