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ELEN [110]
3 years ago
11

Evaluate the sum of the finite geometric series.

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:

descarga la aplicación photomath

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Find the solutions to the equation below check all that apply 4x2 -8x +3 =0
notka56 [123]

Answer:

Hello :

4x² - 8x +3 = 0

4 ( x² - 2x +3/4 ) = 0

4 ( (x² -2x +1) -1 + 3/4) = 0

4 ((x-1)² - 1/4 ) =0

(x-1)² - 1/4 = 0

(x-1)² -  ( 1/2 )²=0

( x - 1 -1/2 ) ( x - 1 +1/2 ) = 0

( x - 3/2) ( x - 1/2) = 0

x - 3/2 = 0 or x - 1/2 = 0

two solutions : 3/2  ; 1/2



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3 years ago
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4 is C. Multiply by 3

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Given the parent functions f(x) = log10 x and g(x) = 3x − 1, what is f(x) • g(x)?
oksano4ka [1.4K]
We are given with two functions f(x) = log10 x and g(x) = 3x − 1 and is asked for the product of the two functions expressed as f(x) • g(x). The answer then is simply the product of the two functions, that is log x * (3x - 1). log 10 x is equal to log x. 
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The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and
Scorpion4ik [409]

Answer:

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

Step-by-step explanation:

The PDF of X is

\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)

The PDF of Y is

\bf g(x)=\mu e^{-\mu x}\;(x\geq0)

The means of X and Y are respectively,

\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

7 0
3 years ago
Alan Jeff and Lucy all take their pets to the same vet. The pets are a dog a cat and a rabbit. The names of the pets are Blackie
zmey [24]

Answer:

i need at least a pick of the problom

Step-by-step explanation:

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3 years ago
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