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3 years ago

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I need help with this question "To estimate the product 3.48 x 7.33,Marisa multiplied 4x8 to get 32.Explain how she can make a c

loser estimate."

1 answer:

Furkat [3]3 years ago

3 0

3.5 x 7.3
Take it to the nearest tenth.
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Need the answer on this

denpristay [2]

None of the answers are correct because it’s definitely not “Given” because x=20 is like an answer. It’s also not “Distributive Property”, “subtraction Property”, and or “Additional Property” b/c there’s nothing that can be distributed, subtract or add. It’s just an answer.

3 0

3 years ago

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joey made a deposit into an account that earns 6% simple interest.After three years, joey had earned $400. How much was joey's i

Sergio [31]

Answer:

Step-by-step explanation:

To find the amount deposited, we will simply use the formula for calculating simple interest.

Simple Interest = pxrxt/100 (fraction)

Where p = principal

R= Rate

T= Time

Principal is the initial amount deposited which we are ask to find.

R is given to be 6% and T is the time which is given in years

Simple interest is the interest earned over the year which is given to be $400

Lets substitute our variable into the equation

Simple Interest = pxrxt/100 (fraction)

$400 = P × 6 × 3 / 100

$400 = 18p/100 (fraction)

We will then cross multiply

$40 000 = 18 P

To get the value of P, we divide both-side of the equation by 18

4000/18 = 18p/18 (fractions)

$2222.22 = P

P = $2222.22

credits: ummuabdallah

3 0

3 years ago

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Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

Reflect polygon P using line L

Maurinko [17]

Answer:

Just align it on the other side.

Step-by-step explanation:

Top right point, count how many units it is from the reflective line. Then count that many units on the other side and place the point. So on so forth.

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3 years ago

Write log146−log14 3 2 as a single logarithm.

Elden [556K]

The answer to this is log14 4

3 0

3 years ago

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