Question

Directions:For questions 12-16 simplify using the given replacement valued. There should be no decimals, convert all decimals to fractions. (Do not change whole numbers)I need help with 14

Answer 1

14. Given:

$\frac{3}{2}r-rs+4,r=\frac{6}{7},s=\frac{2}{3}$

Substitute the value of r and s in the given problem.

We get,

$\begin{gathered} \frac{3}{2}(\frac{6}{7})-(\frac{6}{7})(\frac{2}{3})+4=3(\frac{3}{7})-(\frac{2}{7})(2)+4 \\ =\frac{9}{7}-\frac{4}{7}+4 \\ =\frac{5}{7}+4 \\ =\frac{33}{7} \end{gathered}$

Hence, the answer is

$\frac{33}{7}$