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4 years ago

Solve with completing the square method:6x²-7x+2=0 and ax²+bx+c=0

1 answer:

7 0

$6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^{2}-4ac = (-7)^{2}-4*6*2=49-48=1 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{7-\sqrt{1}}{2*6}=\frac{7-1}{12} =\frac{6}{12}= \frac{1}{ 2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{7+\sqrt{1}}{2*6}=\frac{7+1}{12} =\frac{8}{12}= \frac{2}{ 3}$

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Question:

NNADVOKAT [17]

1.) 9(4) + 8(5)

36 + 40 = 74

2.) 2(3) + 8(3)

6 + 24 = 30

3.) 4(5) + 7(5)

20 + 35 = 55

4.) 10(4) + 18(5)

40 + 90 = 130

5.) 2 + 8(1/4)

2 + 2 = 4

6.) 9(1/3) + 8(1/4)

3 + 2 = 5

7.) 3(8) + 7(4)

24 + 28 = 52

8.) 12(1/4) + 16(5)

4 + 80 = 84

8 0

3 years ago

The sum of two polynomials is â€"yz2 â€" 3z2 â€" 4y 4. If one of the polynomials is y â€" 4yz2 â€" 3, what is the other polynomi

gtnhenbr [62]

The sum of polynomials involves adding the polynomials

The other polynomial is $y^3 -y^2+ 4y - 1$

The sum of the polynomials is given as:

$Sum = y^3 + 3y^2 + 4y - 4$

One of the polynomials is given as:

$P = 4y^2 - 3$

Represent the other polynomial with Q.

So, we have:

$P +Q =Sum$

Substitute the expressions for P and Sum

$4y^2 - 3 +Q =y^3 + 3y^2 + 4y - 4$

Make Q the subject

$Q =y^3 + 3y^2 -4y^2+ 4y - 4 +3$

Evaluate like terms

$Q =y^3 -y^2+ 4y - 1$

Hence, the other polynomial is $y^3 -y^2+ 4y - 1$

Read more about polynomials at:

brainly.com/question/1487158

8 0

3 years ago

Find the value of n so that the expression is a perfect square trinomial and then factor the trinomial.

Anna007 [38]

The correct expression is (a) n = 100; (x + 10)^2

<h3>How to determine the value of n?</h3>

The expression is given as:

x^2 + 20x + n

Take the coefficient of x

k = 20

Divide by 2

k/2= 10

Square both sides

(k/2)^2 = 100

The above value represents the value of n

i.e.

n = 100

So, we have:

x^2 + 20x + 100

Expand

x^2 + 10x + 10x + 100

Factorize

x(x + 10) + 10(x + 10)

Factor out x + 10

(x + 10)^2

Hence, the correct expression is (a) n = 100; (x + 10)^2