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1 year ago

I'm so d*mb‍ i need help i got the answer but i need help with the formulas and showing my work to get the answer

Mathematics

1 answer:

bazaltina [42]1 year ago

5 0

Answer:youre not dum :)

Step-by-step explanation: e

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Which function is a linear function a. 1-3x^2 b. y+7=5x c. x^3 + 4 = y d. 9(x^2-y) = 3 e.y-x^3=8

FrozenT [24]

Answer:

b. y+7=5x

Step-by-step explanation:

a. 1-3x^2 is a quadratic

b. y+7=5x is a linear function: y = 5x - 7

c. x^3 + 4 = y is a cubic function

d. 9(x^2-y) = 3 is a quadratic function

e.y-x^3=8 is a cubic function

3 0

3 years ago

According to a recent survey, 31 percent of the residents of a certain state who are age 25 years or older have a bachelor’s deg

Inga [223]

Answer:

The probability of getting B=40 is $0.11\times 10^{-11}$ which is negligible.

Step-by-step explanation:

Given that 31 percent of the residents of a certain state who are age 25 years or older have a bachelor’s degree.

Assuming the population of the state aged 25 years or more is Bernoulli's population.

So, when 1 person aged 25 years or more from the state selected randomly, the probability of that person, p, having a bachelor’s degree,

$p= 31/100=0.31\cdots(i)$

Now, according to Bernoulli's formula, the probability of exactly r success from the total number of sample n is

$P(r)=\binom{n} {r}p^r(1-p)^{n-r}\cdots(ii)$

where p is the probability of success.

Here, a random sample of 50 residents of the state, age 25 years or older, will be selected.

So, n=50.

Given that variable B represents the number in the sample who have a bachelor’s degree,

We have to find the probability that B will equal 40.

So, r=B= 40.

Now, putting these values in equation(ii) and using p=0.25 from equation (i), we have

$P(r=40)=\binom{50} {40}(0.31)^{40}(1-0.31)^{50-40}$

$=\frac {50!}{40! (50-40)!}(0.31)^{40}(0.69)^{10} \\\\=\frac {50!}{40! \times 10!}(0.31)^{40}(0.69)^{10} \\\\=0.11\times 10^{-11}$

So, the probability of getting B=40 is $0.11\times 10^{-11}$ which is negligible.

4 0

3 years ago

Read 2 more answers

Find the derivative of ln(secx+tanx)

Sliva [168]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3000160

————————

Find the derivative of

$\mathsf{y=\ell n(sec\,x+tan\,x)}\\\\\\ \mathsf{y=\ell n\!\left(\dfrac{1}{cos\,x}+\dfrac{sin\,x}{cos\,x} \right )}\\\\\\ \mathsf{y=\ell n\!\left(\dfrac{1+sin\,x}{cos\,x} \right )}$

You can treat y as a composite function of x:

$\left\{\! \begin{array}{l} \mathsf{y=\ell n\,u}\\\\ \mathsf{u=\dfrac{1+sin\,x}{cos\,x}} \end{array} \right.$

so use the chain rule to differentiate y:

$\mathsf{\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot \dfrac{du}{dx}}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{d}{du}(\ell n\,u)\cdot \dfrac{d}{dx}\!\left(\dfrac{1+sin\,x}{cos\,x}\right)}$

The first derivative is 1/u, and the second one can be evaluated by applying the quotient rule:

$\mathsf{\dfrac{dy}{dx}=\dfrac{1}{u}\cdot \dfrac{\frac{d}{dx}(1+sin\,x)\cdot cos\,x-(1+sin\,x)\cdot \frac{d}{dx}(cos\,x)}{(cos\,x)^2}}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{1}{u}\cdot \dfrac{(0+cos\,x)\cdot cos\,x-(1+sin\,x)\cdot (-\,sin\,x)}{(cos\,x)^2}}$

Multiply out those terms in parentheses:

$\mathsf{\dfrac{dy}{dx}=\dfrac{1}{u}\cdot \dfrac{cos\,x\cdot cos\,x+(sin\,x+sin\,x\cdot sin\,x)}{(cos\,x)^2}}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{1}{u}\cdot \dfrac{cos^2\,x+sin\,x+sin^2\,x}{(cos\,x)^2}}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{1}{u}\cdot \dfrac{(cos^2\,x+sin^2\,x)+sin\,x}{(cos\,x)^2}\qquad\quad (but~~cos^2\,x+sin^2\,x=1)}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{1}{u}\cdot \dfrac{1+sin\,x}{(cos\,x)^2}}$

Substitute back for $\mathsf{u=\dfrac{1+sin\,x}{cos\,x}:}$

$\mathsf{\dfrac{dy}{dx}=\dfrac{1}{~\frac{1+sin\,x}{cos\,x}~}\cdot \dfrac{1+sin\,x}{(cos\,x)^2}}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{cos\,x}{1+sin\,x}\cdot \dfrac{1+sin\,x}{(cos\,x)^2}}$

Simplifying that product, you get

$\mathsf{\dfrac{dy}{dx}=\dfrac{1}{1+sin\,x}\cdot \dfrac{1+sin\,x}{cos\,x}}\\\\\\ \mathsf{\dfrac{dy}{dx}=\dfrac{1}{cos\,x}}$

∴ $\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=sec\,x} \end{array}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>derivative composite function logarithmic logarithm log trigonometric trig secant tangent sec tan chain rule quotient rule differential integral calculus</em>

3 0

3 years ago

Barbara sells iced tea for a $1.49 per bottle and water for $1.25 per bottle. She wrote a equation to find the number of drinks

Debora [2.8K]

Answer B is correct. She forgot to use a variable for 1.49. The correct equasion would be:
$1.25x + 1.49y = 100$

4 0

3 years ago

Read 2 more answers

35 points!!!! WILL GIVE BRAINLIEST

Arturiano [62]

Answer

Find out the length of OP .

To prove

As given

In △JKL, JO=44 in.

Now as shown in the diagram.

JP , MK, NL be the median of the △JKL and intresection of the JP , MK, NL be O .

Thus O be the centroid of the △JKL .

The centroid divides each median in a ratio of 2:1 .

Let us assume x be the scalar multiple of the OP and JO .

As given

JO = 44 in

2x = 44

x = 22 in

Thus the length of the OP IS 22 in .

7 0

3 years ago

Read 2 more answers