Answer is option C
Mr. Jones jogs the same route each day. The amount of time he jogs is inversely proportional to his jogging rate.
k is the constant of proportionality
We check with each option and identify which option gives us same K value
(a) 4 mph for 2.5 hours and 6 mph for 3.75 hours
so k = 10
so k = 22.5
K values are not same
(b) 3 mph for 2 hours and 4.5 mph for 3 hours
so k = 6
so k = 13.5
K values are not same
(c) 4 mph for 2.5 hours and 5 mph for 2 hours
so k = 10
so k =10
K values are same .
Answer is option C
Answer:
O It has the same slope and a different y-intercept.
Step-by-step explanation:
y = mx + b
m = 3/8
b = 12
y = (3/8)x + 12
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Data in the table: slope is the rise (y) over the run (x) between two points (assuming the data represent a linear line).
Change in x and y between two points. I'll choose (-2/3,-3/4) and (1/3,-3/8).
Change in y: (-3/8 - (-3/4)) = (-3/8 - (-6/8)) = 3/8
Change in x: (1/3 - (-2/3)) = (1/3+2/3) = 3/3 = 1
Slope = (Change in y)/(Change in x) = (3/8)/1 = 3/8
The slope of the equation is the same as the data in the table.
Now let's determine if the y-intercept is also the same (12). The equation for the data table is y = (2/3)x + b, and we want to find b. Enter any of the data points for x and y and then solve for b. I'll use (-2/3, -3/4)
y = (3/8)x + b
Use (-2/3, -3/4)
-3/4 =- (3/8)(-2/3) + b
-3/4 = (-6/24) + b
b = -(3/4) + (6/24)
b = -(9/12) + (3/12)
b = -(6/12)
b = -(1/2)
The equation of the line formed by the data table is y = (3/8)x -(1/2)
Therefore, It has the same slope and a different y-intercept.
Answer: B. 0.036
Step-by-step explanation:
Formula for standard error :
, where p = Population proportion and n= sample size.
Let p be the population proportion of the people who favor new taxes.
As per given , we have
n= 170
Substitute these values in the formula, we get
Hence, the standard error of the estimate is 0.036.
∴ The correct answer is OPTION B. 0.036
The slope of these coordinates is - 3/5
Answer: 34.2%
Step-by-step explanation:
76% of undergrads in The College
45% of those are male (since 55% female)
.76 x .45 = 34.2% of all undergrads are males in The College
