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3 years ago

PLEASE HELP I'M BEING TIMED!!!!

Mathematics

2 answers:

Kryger [21]3 years ago

7 0

Answer:

Step-by-step explanation:

Helga [31]3 years ago

3 0

6.3
use the equation 4/3 *r^3 *pi for each, then find the difference

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Write the equation of the line that goes through each set of points (-1,6),(3-2)

Mariana [72]

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-1, 6) and (3, -2). Substitute:

$m=\dfrac{-2-6}{3-(-1)}=\dfrac{-8}{4}=-2\\\\y-6=-2(x-(-1))\\\\y-6=-2(x+1)\qquad\text{use distributive property}\\\\y-6=-2x-2\qquad\text{add 6 to both sides}\\\\y=-2x+4\qquad\text{add 2x to both sides}\\\\2x+y=4$

<h3>Answer:</h3><h3>y - 6 = -2(x + 1) <em>point-slope form</em></h3><h3>y = -2x + 4 <em>slope-intercept form</em></h3><h3>2x + y = 4 <em>standard form</em></h3>

4 0

3 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample

adelina 88 [10]

Answer:

$\sigma = 12.5$ ---- sample standard deviation

$\sigma^2 = 157.2$ ---- sample variance

Step-by-step explanation:

Solving (a): The sample variance

First, we calculate the midpoint of each class (this is the average of the limits)

So, we have:

$x_1 = \frac{56 + 64}{2} = 60$

$x_2 = \frac{65 + 73}{2} = 69$

And so on

So, the table becomes:

$\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}$

Calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}$

$\bar x = \frac{4191}{55}$

$\bar x = 76.2$

The variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}$

$\sigma^2 = \frac{8488.8}{54}$

$\sigma^2 = 157.2$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2$

$\sigma = \sqrt{157.2$

$\sigma = 12.5$

Solving (b): The sample variance

In (a), we calculate the sample variance to be:

$\sigma^2 = 157.2$

6 0

3 years ago

The Monument in Santiago measures 175 meters. A child measures 87.5 centimeters. How much is the Monument taller than the child?

Sedbober [7]

Answer:

The Monument is taller than the child by 174.125 meters

Step-by-step explanation:

The Monument in Santiago measures 175 meters. A child measures 87.5 centimeters.

Step 1

Convert child's height to meters

100cm = 1 m

87.5 cm = x

Cross Multiply

100cm × x = 87.5 cm × 1m

x = 87.5 cm × 1m/100cm

x = 0.875m

Step 2

How much is the Monument taller than the child?

This is calculated by subtracting Child's height from Monument height

= 175 m - 0.875m

= 174.125 m

Therefore, the Monument is taller than the child by 174.125 m

3 0

3 years ago

15 Apple it's all run in a race a gold medal is to be giving to the winner, it's silver medal is to be giving to the 2nd place f

anzhelika [568]

$3!=6$

.............

5 0

3 years ago

Describe, in your own words, the identity sin^2(x) + cos^2(x) = 1.

Crank

Look at the attached figure. We define the unit circle as a circle with center $A$ in the origin (0,0) and radius 1.

Then, we consider a point P on the circumference. We call $\alpha$ the angle between the positive half of the x axis and the radius AP.

We define

$\cos(\alpha) = \overline{AD},\quad \sin(\alpha) = \overline{AC}$

As you can see, ACD is a right triangle, and so we have

$\overline{AD}^2+\overline{AC}^2=\overline{AP}^2$

But since we know that AD is the cosine, AC is the sine, and AP is the radius (which is 1, and remains 1 when squared), we have just found out that

$\cos(\alpha)^2+\sin(\alpha)^2=1$

4 0

3 years ago