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Valentin [98]
3 years ago
12

Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=3, u'(0)= -4, v(0)= 2, v'(0)= -7. Find the value

s of the following derivatives at x=0. A.) d/dx(uv)
Mathematics
2 answers:
3241004551 [841]3 years ago
7 0
\bf \cfrac{d}{dx}[u(x)\cdot v(x)]\implies \cfrac{du}{dx}\cdot v(x)+u(x)\cdot \cfrac{dv}{dx}\quad 
\begin{cases}
u(0)=3\qquad u'(0)=-4
\\\\
v(0)=2\qquad v'(0)=-7
\end{cases}
\\\\
\left[ \cfrac{du}{dx} \right]_{x=0}\cdot v(0)+u(0)\cdot \left[ \cfrac{dv}{dx} \right]_{x=0}

so.. hmm pretty sure you know what that is
grin007 [14]3 years ago
6 0

Answer:

none of these are useful

Step-by-step explanation:

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What are the solutions of x2 +6x-6= 10?
ipn [44]

Answer:

x= -8    x=2

Step-by-step explanation:

x^2 +6x-6= 10

Subtract 10 from each side

x^2 +6x-6-10= 10-10

x^2 +6x-16 = 0

What 2 number multiply to -16 and add to 6

8 * -2 = -16

8 -2 = 6

(x+8) (x-2)=0

Using the zero product property

x+8=0  x-2=0

x= -8    x=2

3 0
2 years ago
HURRY PLS HELP ILL GIVE BRAINLYEST Subtract.
natka813 [3]

Answer:

2940

Step-by-step explanation:

You are subtracting a negative number. "Minus a negative is plus."

525 - (-2415) = 525 + 2415 = 2940

6 0
2 years ago
Read 2 more answers
Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.
SashulF [63]
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

  • <u>where a is side of the cube </u>

\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  6\times 3.2\times3.2   \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  61.44 cm^2  \\\end{gathered}

Now,

\maltese \sf Cost  \:of  \:painting \: 1 \: cm² = \$ 5

\sf Cost \: of \: painting \: 61.44  \:cm²=61.44×5

\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

3 0
2 years ago
Can someone help me solve this?
Sergio [31]

Answer:

m<c = 104°

m<d = 80°

Step-by-step explanation:

Recall: Opposite angles of a cyclic quadrilateral are supplementary. Therefore, their sum equals 180°. Thus:

m<c + 76° = 180°

m<c + 76° - 76° = 180° - 76° (subtraction property of equality)

m<c = 104°

m<d + 100° = 180°

m<d +100° - 100° = 180° - 100° (subtraction property of equality)

m<d = 80°

8 0
2 years ago
Name the postulate or theorem you can use to prove the triangles congruent
Lesechka [4]

Answer:

ASA

Step-by-step explanation:

if you understood the other, similar questions now, this one is really, really easy.

we got the confirmation for 2 angles and the side between these angles.

so, angle side angle or ASA

6 0
2 years ago
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