Answer:
-cos^4(x)
Step-by-step explanation:
Step 1: Use the Pythagorean identity : 1=cos^2(x) + sin^2(x)
1-sin^2(x) = cos^2(x)
-1+sin^2(x) = -cos^2(x)
cos^2(x) (-cos^2(x))
Step 2: Factor out common terms cos^2(x)
cos^2(x) (sin^2(x)-1)
Ans: -cos^4(x)
The given triangle is isosceles, so the two remaining angles in the triangle both have measure <em>xº</em>. The interior angles of any triangle sum to 180º, so that
58º + <em>xº</em> + <em>xº</em> = 180º
58 + 2<em>x</em> = 180
2<em>x</em> = 122
<em>x</em> = 61
Angles <em>y</em> and <em>z</em> are supplementary to angle <em>x</em>, so that
<em>xº</em> + <em>yº</em> = 180º
and
<em>xº</em> + <em>zº</em> = 180º
and consequently, <em>y</em> = <em>z</em>. In particular, we get
<em>y</em> = 180 - 61
<em>y</em> = 119
and so
<em>z</em> = 119
<span>T = 3U / E solve for U
3U = T * E
U = (</span>T * E)/3
U = 1/3(TE)
Answer:
B. -2t^2+3t+4
Step-by-step explanation:
The standard form as
ax^2 + bx + c
Option B meets that requirement, even though it has a '-' in front
