Question

What is the slope-intercept form of the linear equation 2x–8y=32 ?

Answer 1

First write the equation 2x-8y=32
then use the zero method .
to find x intercept let y= 0
so, 2x-8(0)=32
2x=32
2x/2=32/2
x=16
x intercept:(16,0)
then do same for u
let x=0
2(0)-8y=32
-8y=32
-8y/-8=32/-8
y=-4
y intercept: (0,-4)

Answer 2

The answer is (0,-4) (16,0)