Question

A pen stand made of wood is in the shape of a cuboid with four conical depressions to hold pens. The dimensions of the cuboid are 15 cm by 10 cm by 3.5 cm. The radius of each of the depressions is 0.5 cm and the depth is 1.4 cm. Find the volume of wood in the entire stand. Use T = 22/7. O 520.48 cm 523.53 cm O 529.68 cm 0 528.74 cm

Answer 1

$Volume=523.53\text{ }cm^3$

Explanation

Step 1

Let

Length=15 cm

width=10 cm

depth=3.5 cm

radius = 0.5 cm

depth depression=1.4

draw

Step 2

so, the volume of the wood is

$\begin{gathered} \text{Volume}=\text{volume of the block- volume of 4 depresssion} \\ \text{replacing} \\ \text{Volume}=(15\text{ cm}\cdot\text{ 10 cm}\cdot\text{ 3.5 cm)-4(}\frac{1}{3}(\pi\cdot(0.5cm)^2)\cdot1.4) \\ \text{Volume}=525cm^3-1.46cm^3 \\ Volume=523.53\text{ }cm^3 \end{gathered}$

I hope this helps you