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Studentka2010 [4]
3 years ago
5

What are the coordinates of S?

Mathematics
1 answer:
ehidna [41]3 years ago
3 0

Answer:

(-2,6) is the codinates of S

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What is the slope and equation of the graph?
jasenka [17]

Answer:

Looks like the slope is -(1/2) and the equation is y= -(1/2)x + 1

3 0
3 years ago
Compare the Following Ratios 7to 12 ________ 7/8<br><br> A: &gt;<br> B: &lt;<br> C: =
ser-zykov [4K]

Change the ratios to decimals and compare:

7 / 12 = 0.583

7 / 8 = 0.875

So 7:12 is less than 7/8

The answer is <

7 0
3 years ago
The surface area of the prism is ______ square units. All measurements in the image below are in units. (Input whole number only
White raven [17]
To find the area of a triangle, use 1/2 x b x h.  3 x 4 = 12    1/2 of 12 = 6

There are two triangles, each of these are 6      6 x 2 = 12

The bottom shape is 3.5 x 3      3.5 x 3 = 10.5

The front shape is 3.5 x 5      3.5 x 5 = 17.5

The back shape is 3.5 x 4        3.5 x 4 = 14

Add them all together: 14 + 17.5 + 10.5 + 12 = 54

Your answer is 54!
7 0
3 years ago
HELLLLPPPPPPPP PLEASEEEEEEEEE
tatyana61 [14]

Answer:

10.5

Step-by-step explanation:

KET\cong KIT...... (given)

\therefore KE \cong KI.... (csct)

\therefore m(KE) =m(KI)

\therefore 10x-34= 4x + 29

\therefore 10x-4x= 34 + 29

\therefore 6x= 63

\therefore x=\frac{63}{6}

\therefore x=10.5

4 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
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