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Setler [38]
1 year ago
6

Question 1 (10 points)

Mathematics
1 answer:
GuDViN [60]1 year ago
5 0

= 2^{3}  \\  = 2 \times 2 \times 2 \\  = (2 \times 2) \times 2 \\  = 4 \times 2 \\  = 8

ATTACHED IS THE SOLUTION

LAST OPTION IS THE ANSWER.

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How do you solve -24=2r
Svetach [21]
The answer is: r = -12
7 0
3 years ago
Please help me!!!!!! I really neeeeeeed
Butoxors [25]

Answer:

A-(x+4,y-5)

B- move 1 unit left and 7 units down

Step-by-step explanation:

A- 4 units right is x so

(x+4,y__)

5 units down is y so

(x+4,y-5)

B- move 1 unit left and 7 units down

because (x-1,y__) is going left because of the subtraction sign and its the x-coordinate, and (x-1,y-7) is down because its a Y-coordinate and sub so its going down.

<h2><u>TIP- Going left/down is always subtract/negative going right/up is positive/addition.</u></h2>
6 0
3 years ago
Identify the range of the function shown in the graph.
dezoksy [38]

where's the graph? ( ಠ_ಠ)

8 0
3 years ago
Read 2 more answers
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
1. Are we limited to using a trigonometric function only in cases of an object that has a cyclical behavior? Is it possible to m
pentagon [3]

Trigonometric functions are not only used in cases of an object that has a cyclical behavior.

<h3>What is a trigonometric function?</h3>

It should be noted that trigonometric functions are real functions that relate the angle of a right angled triangle to the ratios of the two side lengths.

Trigonometric functions are not only used in cases of an object that has a cyclical behavior. It can be used to obtain unknown <em>angles</em> in geometric figures.

It can also be used to model the fluctuations in temperature data for a particular year.

The movement of a yo-yo can be modeled by a sinusoidal curve since it exhibits a periodic behavior.

Learn more about trigonometry on:

brainly.com/question/24349828

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2 years ago
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