Answer:
v_top = 2400 mi/hr
v_w = 400 mi/h
Step-by-step explanation:
Given:
- Total distance D = 4800 mi
- Headwind journey time taken t_up= 3 hr
- Tailwind journey time taken t_down = 2 hr
Find:
Find the top speed of Luke's snow speeder and the speed of the wind.
Solution:
- The speed of Luke v_l is in stationary frame is given by:
v_l = v_w + v_l/w
Where,
v_w: Wind speed
v_l/w: Luke speed relative to wind.
- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:
v_top = D / t_down
v_top = 4800 / 2
v_top = v_down = 2400 mi/hr
- Similarly his speed on his journey up with head wind was v_up:
v_up = D / t_up
v_up = 4800 / 3
v_up = 1600 mi/hr
- Now use the frame relations to find the wind speed v_w:
v_down = v_w + v_l/w
v_up = -v_w + v_l/w
- Solve equations simultaneously:
2400 = v_w + v_l/w
1600 = -v_w + v_l/w
4000 = 2*v_l/w
v_l/w = 2000 mi/h
v_w = 400 mi/h
Answer:
380
Step-by-step explanation:
Find 1% of e:
180 / 45 = 4
Find 95% of e:
4 * 95 = 380
Both of those times are in two standard deviations, so the percent would be 95%.
The mistake is made on line 3, after calculating 35/7, he should have started with the multiplication 6(2)
Answer:
S = (5m+79)
Step-by-step explanation:
It is given that,
Scores won by home team = (2m + 39) points
Score won by visiting team = (3m + 40) points
We need to find the sum to represent the total points scored by the two teams m minutes past halftime.
It can be calculated by the sum of score by two teams. Let the sum is S.
S = (2m + 39) + (3m + 40)
S = 5m + 79
Hence, sum to represent the total points scored by the two teams m minutes past halftime is (5m+79)