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HACTEHA [7]
2 years ago
11

Print, then use the following image to create a tangent line. Upload the constructed image as your final answer.

Mathematics
1 answer:
tia_tia [17]2 years ago
4 0

Answer:

steps below

Step-by-step explanation:

To construct tangent line to a circle based on two main properties of tangent line and inscriber triangle of circle

1. A line is tangent to a circle when it intersects the circle in one point. At that point, the radius of the circle forms a right angle with the tangent line. If the radius forms a right angle with the tangent line, <u>then the segment OP becomes the hypotenuse of the right triangle.</u>

2. a triangle inscribed in a circle having a diameter (OT) as one side is a right triangle.

Construction:

1. connect P and circle center "O"

2. construct perpendicular bisector of PO --- AB, Intersect M will be the center of new circle and its radius is MP

3. With the center of "M" and radius MP: construct a circle and intersect original circle at "T" and "T'"

4. PT and PT' are the tangent lines

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15 - 10 = _____(3 - 2) PLEASE HELP ON THIS IS DUE TODAY
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Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
3 years ago
Please help with this question
Dafna1 [17]
The answer is (-2,-3)  Thank you and please rate if I helped you! Thanks again!
4 0
2 years ago
Basically im on lvl 2 for this Geometry question, need help!!​
aniked [119]

Answer:D.10x=150

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7 0
3 years ago
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