What is the context for the question if there is any?
(f + g)(x) = f(x) + g(x)
(f + g)(x) = 3x + 5 + x^2 = x^2 + 3x + 5
Answer: Choice D
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Answer:
- 1) y = (-2/3)x +2/3
- 2) y = (6/5)x -23/5
- 5) y = (-1/6)x +4/3
- 6) y = x -2
Step-by-step explanation:
A simple, mechanical way to do these (perpendicular lines) is ...
- replace any constant with 0
- swap the x- and y-coefficients, negating one
- for point (h, k), replace x with (x-h) and y with (y-k)
- solve for y (to get slope-intercept form)
1) 3x -2y = 0 . . . . . step 1
... 2x +3y = 0 . . . . step 2
... 2(x -1) +3(y -0) = 0 . . . . step 3
... 2x -2 = -3y . . . . eliminate parentheses, subtract 3y
... y = (-2/3)x +2/3 . . . . divide by the coefficient of y
2) 6(x -3) -5(y +1) = 0 . . . . after step 3
... 6x -23 = 5y . . . . . . . . . . simplify, add 5y
... y = (6/5)x - 23/5 . . . . . divide by the coefficient of y
5) (x+4) +6(y-2) = 0 . . . . . after step 3
... x -8 = -6y . . . . . . . . . . . simplify, subtract 6y
... y = (-1/6)x +4/3 . . . . . . divide by the coefficient of y
6) (y +5) = (x +3) . . . . . . . after step 3
... y = x -2 . . . . . . . . . . . . subtract 5