Ask question

Ask question

All categories

11 months ago

13

5x^2=11x-2 quadratic equation

1 answer:

hjlf11 months ago

4 0

Given data:

The given equation is 5x^2= -11x-2.

The given equation can be written as,

$\begin{gathered} 5x^2=-11x-2 \\ 5x^2+11x+2=0^{} \\ 5x^2+10x+x+2^{} \\ 5x(x+2)+1(x+2)=0 \\ (5x+1)(x+2)=0 \\ x=-\frac{1}{5},\text{ x=-2} \end{gathered}$

Thus, the values of x are x=-1/5, and x= -2.

You might be interested in

Find the values of x and y if 5 ˣ⁻³ x 3²ʸ⁻⁸ =225

-BARSIC- [3]

Answer:

x = 5, y = 5

Step-by-step explanation:

${5}^{x - 3} \times {3}^{2y - 8} = 225 \\ {5}^{x - 3} \times {3}^{2y - 8} = 25 \times 9 \\ {5}^{x - 3} \times {3}^{2y - 8} = {5}^{2} \times {3}^{2} \\ equating \: like \: power \: terms \: from \: both \:\\ sides \\ {5}^{x - 3} = {5}^{2} \\ x - 3 = 2 (Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ x = 3 + 2 \\ \huge \red{ \boxed{ x = 5}} \\ \\ {3}^{2y - 8} = {3}^{2} \\ 2y - 8 = 2(Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ 2y = 2 + 8 \\ 2y = 10 \\ y = \frac{10}{2} \\ \huge \purple{ \boxed{y = 5}}$

5 0

2 years ago

Can someone define the word of an pre-image in math

d1i1m1o1n [39]

Answer:

The image before a transformation is performed.

Step-by-step explanation:

Hope it helps!

This means the image that was there before a translation, reflection, rotation, or dilation was performed.

4 0

1 year ago

Read 2 more answers

2x+3y=12 find y and x intercepts

lord [1]

Answer:

Linear function 2x+3y=12 .

Step-by-step explanation:

To find y-intercept , make x=0 :

3y = 12

y = 12/3

y = 4 .

To find x-intercept , make y=0 :

2x = 12

x = 12/2

x = 6 .

<u> ! Hope this will help you !</u>

8 0

3 years ago

Find the indefinite integral. (Use C for the constant of integration.)

mart [117]

Answer:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

$u=(x^3-x^2+x)$

Then

$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

7 0

2 years ago

THE SUM OF TWO INTEGERS WITH DIFFERENT SIGNS IS 8.GIVE TWO POSSIBLE INTEGERS THAT FIT THIS DESCRIPTION.

marusya05 [52]

Sum of two integers with different signs is equal to 8.

There are several answers:

+12 and -4
+10 and -2
+11 and -3

ETC.

6 0

3 years ago