Cookies are on sale! Today each cookie costs

1 answer:

5 0

Whats the question?
I think the question is "how much are 7 of them if the sale wasn't going on."
which, without the sale, each cookie is originally $1.5, multiplied by 7, is $10.5 so you save a lot of money.
i think this was your question

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6.493 rounded to the hundredths

Nana76 [90]

The answer is 6. 49 you welcome :)

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3 years ago

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If n = 11 and p = 5 what is the value of the expression 18 - n - 2 + p

yan [13]

Answer:

Step-by-step explanation:

If n = 11 and p = 5, we can just substitute the values in for n and p in the equation 18 - n - 2 + p.

The new equation would be 18 - 11 - 2 + 5.

Using PEMDAS, we get the answer of 10.

18 - 11 = 7

7 - 2 = 5

5 + 5 = 10

Hope this helps!

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2 years ago

Solve the equation.round to the nearest thousandths -5+2in(3x)=5

Crank

What is the "in" for in your equation? Repost.

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3 years ago

Identify the variable in: 7h + 3

7nadin3 [17]

Isn’t it h?

extra words so i can actually post this reply

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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

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3 years ago