Answer:
76
2 real solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Standard Form: ax² + bx + c = 0
Discriminant: b² - 4ac
- Positive - 2 solutions
- Equal to 0 - 1 solution
- Negative - No solutions/Imaginary
Step-by-step explanation:
<u>Step 1: Define</u>
x² - 6x - 10 = 0
<u>Step 2: Identify Variables</u>
<em>Compare quadratic.</em>
x² - 6x - 10 = 0 ↔ ax² + bx + c = 0
a = 1, b = -6, c = -10
<u>Step 3: Find Discriminant</u>
- Substitute in variables [Discriminant]: (-6)² - 4(1)(-10)
- [Discriminant] Evaluate exponents: 36 - 4(1)(-10)
- [Discriminant] Multiply: 36 + 40
- [Discriminant] Add: 76
This tells us that our quadratic has 2 real solutions.
Answer:
x=0
Step-by-step explanation:
Answer:
The vertex form is: y = 3(x-2)^2 + 7
. The vertex is (2, 7)
Step-by-step explanation:
Write the function: y = 3x^2 - 12x + 11 in vertex form
The vertex form of a quadratic equation is:
y = m(x - a)^2 + b where (a,b) is the vertex
For y = 3x^2 - 12x + 11
Solve for m
y = 3(x^2 - 4x) + 11
Complete the Square:
y = 3(x^2 - 4x + 4) + 11 - 4
y = 3(x - 2)^2 + 7
The vertex then is (2, 7)
Answer:
6y/8+12-12=84-12
6y/8=72
8/6*6y/8=72*8/6
y=96
Step-by-step explanation:
first u get rid of the 12 by subtracting it from both side until u get 6y/8 =72. Then to isolate y u have to multiply the reciprocal of 6/8(8/6) by 6y/8, and u do the same thing to the other side. Then when they cancel out each other y would be left to equal 96.
