9514 1404 393
Answer:
1731 ft
Step-by-step explanation:
The tangent relation is useful in this problem.
Tan = Opposite/Adjacent
The height of the light is found to be ...
tan(11°) = height/(639 ft)
height = (639 ft)·tan(11°) . . . . . solve for height
Then the distance from the light to point B is ...
tan(3°) = height/(B distance)
B distance = height/tan(3°) = (639 ft)·tan(11°)/tan(3°) ≈ 2370 ft
Then the distance from point A to point B is ...
2370 ft -639 ft = 1731 ft . . . AB distance
Answer:
f(k) = 2*k + 1
Step-by-step explanation:
The 'f' function takes the variable, doubles it, and then adds 1.
So f(k) = 2*k + 1
f(g) = 2*g + 1
f(m) = 2*m + 1, and so on
It doesn't really matter which variable you use, the function still does the same thing to it.
Negative 36 and negative 3
To solve this, you will have to set up your equation as fractions:
X is to 4 as 4 is to 4+3, or 7
X/4 = 4/7
You will then cross multiply
7x = 4•4
7x = 16
Divide.
X = 2.285714...
Round to the nearest hundredth.
2.29
X=6 and CD Is 11 and AB is 9