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Blizzard [7]
1 year ago
11

a classroom has 24 bulbs and four of the bulbs are failed. how many arrangements are the four failed bulbs are possible?

Mathematics
1 answer:
astraxan [27]1 year ago
8 0

Answer:

Step-by-step explanation:

3

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Divide: (5 + 4i) / (-3 – 2i)
Phantasy [73]

Answer:

<h2>-23/13 - 2/13i</h2>

Step-by-step explanation:

\frac{5+4i}{-3-2i}\\\\\mathrm{Apply\:complex\:arithmetic\:rule}:\\\\\quad \frac{a+bi}{c+di}\:=\:\frac{\left(c-di\right)\left(a+bi\right)}{\left(c-di\right)\left(c+di\right)}\:=\:\frac{\left(ac+bd\right)+\left(bc-ad\right)i}{c^2+d^2}\\\\a=5,\:b=4,\:c=-3,\:d=-2\\\\=\frac{\left(5\left(-3\right)+4\left(-2\right)\right)+\left(4\left(-3\right)-5\left(-2\right)\right)i}{\left(-3\right)^2+\left(-2\right)^2}\\\\Refine\\=\frac{-23-2i}{13}\\\\

\mathrm{Rewrite\:}\frac{-23-2i}{13}\mathrm{\:in\:standard\:complex\:form:\:}-\frac{23}{13}-\frac{2}{13}i\\

8 0
3 years ago
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