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Blizzard [7]
1 year ago
11

a classroom has 24 bulbs and four of the bulbs are failed. how many arrangements are the four failed bulbs are possible?

Mathematics
1 answer:
astraxan [27]1 year ago
8 0

Answer:

Step-by-step explanation:

3

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At the deli, 2 turkey subs and 5 veggie subs cost $29. 4 turkey subs and 3 veggie subs cost
MrMuchimi

Answer:

4/9 of sales are veggie 5/9 are turkey

4/(4+5)=4/9

5/(4+5)= 5/9

4/9 x 27 = 12

5/9 x 27 = 15

12 veggie subs sold and

15 turkey subs sold

12+15=27 total sold

Step-by-step explanation:

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3 years ago
HELP PLZ<br><br> 7k + 4s = 20<br> -8k + 2s = 10<br><br> What is the value of k?
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Divide 20 by 4=5
then 5 by 7=5/7

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3 years ago
Please help brainlist. &lt;3
sertanlavr [38]

Answer:The graph line has to go  through the origin in order for it to be proportional .In a proportional relationship, one variable is always a constant value. Only have 2

Step-by-step explanation:

4 0
3 years ago
Find formula of s in terms of a, b, cos(x)
Alecsey [184]

Answer:

\displaystyle s = \frac{2ab\cos x}{a+b}

Step-by-step explanation:

We want to find a formula for <em>s</em> in terms of <em>a, b, </em>and cos(x).

Let the point where <em>s</em> intersects AB be D.

Notice that <em>s</em> bisects ∠C. Then by the Angle Bisector Theorem:

\displaystyle \frac{a}{BD} = \frac{b}{AD}

We can find BD using the Law of Cosines:

\displaystyle BD^2 = a^2 + s^2 - 2as \cos x

Likewise:

\displaystyle AD^2 = b^2+ s^2 - 2bs \cos x

From the first equation, cross-multiply:

bBD = a AD

And square both sides:

b^2 BD^2  =a^2 AD^2

Substitute:

\displaystyle b^2 \left(a^2 + s^2 - 2as \cos x\right) = a^2 \left(b^2 + s^2 - 2bs \cos x\right)

Distribute:

a^2b^2 + b^2s^2 - 2ab^2 s\cos x = a^2b^2 + a^2s^2 - 2a^2 bs\cos x

Simplify:

b^2 s^2 - 2ab^2 s \cos x = a^2 s^2 - 2a^2 b s \cos x

Divide both sides by <em>s </em>(<em>s</em> ≠ 0):

b^2 s -2ab^2 \cos x = a^2 s - 2a^2 b \cos x

Isolate <em>s: </em>

b^2 s - a^2s = -2a^2 b \cos x + 2ab^2 \cos x

Factor:

\displaystyle s (b^2 - a^2) = 2ab^2 \cos x - 2a^2 b \cos x

Therefore:

\displaystyle s = \frac{2ab^2 \cos x - 2a^2 b \cos x}{b^2- a^2}

Factor:

\displaystyle s = \frac{2ab\cos x(b - a)}{(b-a)(b+a)}

Simplify. Therefore:

\displaystyle s = \frac{2ab\cos x}{a+b}

5 0
3 years ago
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