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docker41 [41]
10 months ago
14

Suppose angles a and B are the two acute angles in a right triangle and that b < a. Apply the relationship between sine and c

osine todetermine which statements are correct.sin(6x - 10) = cos(4x + 10)A)x = 9B)a = 46°a = 48°D)B = 42°E)B = 44
Mathematics
1 answer:
Valentin [98]10 months ago
5 0

The right statements are: A, B and E

Sin(A)=cos(B)

then we check if using x=9 this holds true:

sin(6x-10)=cos(4x+10)

sin((6*9)-10) = sin(44º)

cos(4x+10)=cos(46)

Sin(44)=0.694=cos(46)

then a is true

Now, we know that b

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3 years ago
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olganol [36]

Answer:

f(x) = x^{3} + 4x^{2} -7x^{} -10^{}

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where α = -5, β = -1, and ω = 2

f(x)=(x-(-5) )(x -(-1))(x - 2) = (x+5)(x+1)(x-2)\\\\f(x)=(x+5)(x^{2} -2x + x -2) = (x+5)(x^{2}  -x-2)\\\\f(x)=x(x^{2}  -x-2)+5(x^{2}  -x-2)\\\\f(x)= x^{3} - x^{2} -2x + 5x^{2} - 5x - 10\\\\f(x)= x^{3} + 4x^{2} -7x - 10

<em>NB: To arrive at the answer, expand the brackets and after expansion, collect like terms to obtain the final answer</em>

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3 years ago
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