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docker41 [41]
8 months ago
14

Suppose angles a and B are the two acute angles in a right triangle and that b < a. Apply the relationship between sine and c

osine todetermine which statements are correct.sin(6x - 10) = cos(4x + 10)A)x = 9B)a = 46°a = 48°D)B = 42°E)B = 44
Mathematics
1 answer:
Valentin [98]8 months ago
5 0

The right statements are: A, B and E

Sin(A)=cos(B)

then we check if using x=9 this holds true:

sin(6x-10)=cos(4x+10)

sin((6*9)-10) = sin(44º)

cos(4x+10)=cos(46)

Sin(44)=0.694=cos(46)

then a is true

Now, we know that b

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Which of the following equations below is a linear inequality?
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Answer:

D

Step-by-step explanation:

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4 0
2 years ago
0.8) 498 what is the answer​
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Step 1: We make the assumption that 498 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=498$100%=498​.

Step 4: In the same vein, $x\%=4$x%=4​.

Step 5: This gives us a pair of simple equations:

$100\%=498(1)$100%=498(1)​.

$x\%=4(2)$x%=4(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{498}{4}$

100%

x%​=

498

4​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{4}{498}$

x%

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4

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$\Rightarrow x=0.8\%$⇒x=0.8%​

Therefore, $4$4​ is $0.8\%$0.8%​ of $498$498​.

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2 years ago
Pls help asap! Due in 5 minutes!!! Pls
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Answer: The value of X is 26.

Explanation: The explanation is in the image.

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