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lara [203]
1 year ago
12

For Exercises 4-16, use inductive reasoning to find the next two terms in each sequence, insertyour sketches for 12, 14, and 16.

Mathematics
1 answer:
Elden [556K]1 year ago
3 0

4) For this sequence, what we have to do is express all the terms with the denominator equal to 6

\begin{gathered} \frac{1}{6} \\ \frac{2}{6}\to\frac{1}{3} \\ \frac{3}{6}\to\frac{1}{2} \\ \frac{4}{6}\to\frac{2}{3} \\ \frac{5}{6} \\ \frac{6}{6}\to1 \end{gathered}

Then the 2 values that follow the sequence are:

\frac{5}{6}\text{ , 1}

5) For this sequence we can see that we only have to add the consecutive numbers:

\begin{gathered} 0+1=1 \\ 1+2=3 \\ 3+3=6 \\ 6+4=10 \\ 10+5=15 \\ 15+6=21 \\ 21+7=28 \\ 28+8=36 \end{gathered}

Then the 2 values that follow the sequence are:

28,36

6) For this sequence we can see that the consecutive numbers are squared:

\begin{gathered} 1^2\to1 \\ 2^2\to4 \\ 3^2\to9 \\ 4^2\to16 \\ 5^2\to25 \\ 6^2\to36 \\ 7^2\to49 \\ 8^2\to64 \end{gathered}

Then the 2 values that follow the sequence are:

49,64

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Answer would be 7 since 2 is a negative you would subtract it from 9
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Look at the figure. Which trigonometric ratio should you use to find x?
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Answer:

B.  Sine.

Step-by-step explanation:

We need to find the value of x which is opposite to the given angle  (50 degree).  Also we are given the length of the hypotenuse.

Sine = opposite / hypotenuse so we would use the sine.

Its worth committing this mnemonic to memory, which helps to find the required trig ratio:

SOH-CAH-TOA.

SineOpposite/Hypotenuse- CosineAdjacent/Hypotenuse-TangentOpposite/Adjacent.

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2 years ago
The prime factorization of a number is 2 with a small 3 at the top x9 explain why this is correct or incorrect?​
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It is correct !!!!!!!
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Suppose it is known that 10% of all people in Texas have a specific blood type. Suppose we take a random sample of 500 Texas res
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check the attached file below

5 0
3 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
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