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lozanna [386]
1 year ago
11

Find the surface area of a rectangle solid with edges of length 2cm,5cm, and 7cm

Mathematics
1 answer:
MissTica1 year ago
6 0

The surface area for a rectangular prism is given to be:

A=2(lw+lh+wh)

where l, w, and h are the lengths of the solid.

From the question, we have:

\begin{gathered} l=2\text{ cm} \\ w=5\text{ cm} \\ h=7\text{ cm} \end{gathered}

Therefore, the volume is calculated to be:

\begin{gathered} A=2((2\times5)+(2\times7)+(5\times7)) \\ A=2(10+14+35) \\ A=2(59) \\ A=118\text{ cm}^2 \end{gathered}

The surface area is 118 square centimeters.

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1) 2 1/3 is also equal to 7/3

4 1/5 is also equal to 21/5

you need to make the denominators the same so you have to find the lowest common multiple, which is 15 since both 5 and 3 can be times by to make 15

you need to also times the numerators by the number you're timesing the denominator by

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now just convert 98/15 back to a mixed fraction

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6  \frac{8}{15}

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True because the rectangle represents the universe and closed figures. 
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