Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
Answer:
281/2/5 miles
Step-by-step explanation:
469/5 = 93.8
93.8x3 = 281.4
= 281/2/5 miles
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Answer:
they drink 1.667 gallons a week. it takes about 6.5 days to drink a whole gallon
Step-by-step explanation:
take 10/6 to get 1.667 then how many days would it take to drink 1 whole gallon
Answer:
t = 6.3
Step-by-step explanation:
N=Noe^(-kt)
No = 14 grams
k = .1092
We want to find t when N = 7 or 1/2 of 14
N=Noe^(-kt)
7 = 14 e ^ (-.1092t)
Divide each side by 14
1/2 = e ^ (-.1092t)
take the natural log of each side
ln (1/2) = ln e ^ (-.1092t)
ln (1/2) = -.1092t
Divide each side by -.1092
ln (1/2)/ -.1092 = t
t≈6.3475
Rounding to the nearest tenth
t = 6.3
