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Marta_Voda [28]

1 year ago

11

The perimeter of a rectangle measuring (2x + 2)cm by (3x -3) cm is 58cm. Calculate its area. 13. The perimeter

1 answer:

Stella [2.4K]1 year ago

3 0

Given:

The length of the given rectangle is l =(2x+2) cm.

The width of the given rectangle is w =(3x-3) cm.

The perimeter of the given rectangle is P =58cm.

Required:

We need to find the area of the rectangle.

Explanation:

Consider the perimeter of the rectangle formula.

$P=2(l+w)$

Substitute l=2x+2, w =3x-3 and P=58 in the formula.

$58=2(2x+2+3x-3)$ $58=2(5x-1)$ $58=10x-2$

Add 2 to both sides of the equation.

$58+2=10x-2+2$ $60=10x$

Divide both sides by 10.

$\frac{60}{10}=\frac{10x}{10}$ $x=6$

Substitute x =6 in the equations l=2x+2.

$l=2x+2=2(6)+2=12+2=14cm$ $Substitute\text{ }x=6\text{ }in\text{ }the\text{ }equations\text{ }w=3x-3.$ $w=3x-3=3(6)-3=18-3=15cm$

The area of the rectangle is

$A=lw$

Substitute l=14cm and w =15cm in the formula.

$A=14\times15$ $A=210cm^2$

Final answer:

The area of the given rectangle is 210 square cm.

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frosja888 [35]

Answer:

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Step-by-step explanation:

Given: The side of a regular hexagon is 3 feet.

To find: Area of the hexagon

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It is given that the side of a regular hexagon is 3 feet.

We know that the area of a regular hexagon whose side is a units is $\frac{3\sqrt{3} }{2} a^{2}$

Here, the side is 3 feet

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