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Ivan
3 years ago
9

Find the radius of the congruent circles. Thanks and hope you have a good rest of your day!!

Mathematics
1 answer:
Daniel [21]3 years ago
8 0

Answer:

the radius is 10 since 10 plus ten is 20

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Identify the polygon and classify it as regular or irregular.
Ray Of Light [21]
A regular hexagon has sides that are all congruent and angles that all measure 120 degrees. This means the angles of a regular hexagon add up to 720 degrees. ... An irregular hexagon has sides that are not the same measurement and can have points facing inward as well as outward.

5 0
3 years ago
Read 2 more answers
Help this makes no sense to me and its due in 1 day
Ganezh [65]

First we can find the line RT which is the square root of 40^2-32^2 which is equal to 24.

RT=24

Right Triangle Altitude Theorem Part: The measure of the altitude drawn from the vertex of the right angle of a right triangle to its hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse.

The geometric mean of 32 and TS is 24, so set up equation.

2nd root or square root of 32*TS=24

32*TS=576

TS=18

QS=18+32=50

I hope this answer helped if you have any questions feel free  to ask me in the comments.

7 0
3 years ago
2 numbers whose sum is 23 and difference is -81
xz_007 [3.2K]
What are you trying to say?
5 0
3 years ago
Match each whole number with a rational exponential expression. HELPP ME PLEEASE FASTTT
nalin [4]
1. 343^(2/3)
3rdrt[(343(343)]
49

2. [2,197^(1/3)]^2
[3rdrt(2,197)]^2
169

3. 729^(2/3)
3rdrt[729(729)]
81

4. (1,000^2)^(1/3)
3rdrt(1,000^2)
100

5. [3rdrt(9261)]^2
441

6. [3rdrt(216^2)]
36


Hope this helps!
5 0
3 years ago
Read 2 more answers
Please help due in 20 minutes
MissTica
  • <PTQ=90

In ∆PTQ

Apply Pythagorean theorem

\\ \tt\hookrightarrow PT^2=PQ^2+QT^2

\\ \tt\hookrightarrow PT^2=15.4^2+9.3^2=323.16

\\ \tt\hookrightarrow PT=17.9

In ∆TRQ

\\ \tt\hookrightarrow tan44.4=\dfrac{QT}{TR}=\dfrac{9.3}{TR}

\\ \tt\hookrightarrow 0.9=\dfrac{9.3}{TR}

\\ \tt\hookrightarrow TR=\dfrac{9.3}{0.9}=10.3

  • PR=PT+TR=10.3+17.9=28.2cm

Now

Area:-

\\ \tt\hookrightarrow 1/2bh

\\ \tt\hookrightarrow 1/2(28.2)(9.3)

\\ \tt\hookrightarrow 14.1(9.3)

\\ \tt\hookrightarrow 131.13cm^2

7 0
2 years ago
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