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Karo-lina-s [1.5K]
1 year ago
13

How to find the area of a regular hexagon with a radius of 12 inches? Please help

Mathematics
1 answer:
Volgvan1 year ago
8 0
\begin{gathered} In\text{ this case, as a regular hexagon} \\ \text{radius = side} \\ Area\text{ =}3\cdot\frac{\sqrt[]{3}side^2}{2} \\ \text{side}=12in \\ side^2=144in^2 \\ Area\text{ =}3\cdot\frac{\sqrt[]{3}\cdot(144in^2)}{2} \\  \\ \text{Area}=374.1in^2 \\ \text{The regular hexagon's area is }374.1in^2 \end{gathered}

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Simplify -2x + 5x + 10 - 8
SOVA2 [1]

Answer:

3x+2

Step-by-step explanation:

7 0
4 years ago
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Determine the value of k that partitions a segment into a ratio of 1:4
tiny-mole [99]
1/5 is the value but all you do is take the first number which would be your numerator and add both the first and last number together to get your denominator

3 0
3 years ago
Your office parking lot has a probability of being occupied of 1/3. You happen to find it unoccupied for nine consecutive days.
olasank [31]

Answer:

0.4

Step-by-step explanation:

Let X be the random variable that represents the number of consecutive days in which the parking lot is occupied before it is unoccupied. Then the variable X is a geometric random variable with probability of success p = 2/3, with probability function f (x) = [(2/3)^x] (1/3)

Then the probability of finding him unoccupied after the nine days he has been found unoccupied is:

P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9). For a geometric aeatory variable:

P (X> = 10) = 1 - P (X <10) = 0.00002

P (X> = 9) = 1 - P (X <9) = 0.00005

Thus, P (X> = 10 | X> = 9) = P (X> = 10) / P (X> = 9) = 0.00002 / 0.00005 = 0.4.

6 0
3 years ago
Help im just doing this for my brother :C
cluponka [151]

Answer:

578

Step-by-step explanation:

118 + 560 = 678

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578 is your answer

5 0
3 years ago
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Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a
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We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.

Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4

4 does not equal -8, therefore

The limit does not exist
4 0
3 years ago
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