All categories

1 year ago

How to solve and answer:1 1/3(9-6x)=-11

Mathematics

2 answers:

Y_Kistochka [10]1 year ago

6 0

Answer:

x = 2.875

Step-by-step explanation:

1 1/3 (9 - 6x) = -11

12 - 8x = -11

- 8x = -23

x = 2.875

EleoNora [17]1 year ago

3 0

Solving an equation like this means to find the value of the variable. Here, the variable is x. Solve the left side normally.

Given: 1/3(9 - 6x) = -11
Distribute: 1/3(9) + 1/3(-6x) = -11
When operating with constant numbers on a variable term, apply affects of the operation on the coefficient. So, 1/3(-6x) = -2x.
3 - 2x = -11
Isolate the variable: 3 - 3 - 2x = -11 - 3
-2x = -14
Since these are both negative, we can convert them both to being positive.
2x = 14
Simplify: 2x/2 = 14/2
<u>x = 7</u>

You might be interested in

PLS HELP ILL MARK BRAINLIEST PLS HURRY IM GETTING TIMED!!!!!!!!!

Dennis_Churaev [7]

Answer:

100

Step-by-step explanation:

1.50*100

6 0

2 years ago

What is the GCF of the numerator and denominator in the following fraction? -99/176

Lady bird [3.3K]

-99 = -9*11
176 = 16*11

Both factorizations have 11 show up. It turns out that 11 is the largest common factor.

Answer: C) 11

Note: if you divide both numerator and denominator by 11, then the fraction reduces to -9/16

8 0

3 years ago

Read 2 more answers

Students at a school will sell hats to raise money. There are some hats left over from last year, and 20 boxes of hats will be o

inna [77]

Answer: A) 480

Step-by-step explanation:

x=20 substitute in the two equations

48(20)+37

24(20)+37

since the question said fewer , then you should subtract

48(20)+37 - 24(20)+37 = (960+37) - (480+37)

=923 - 443= 480

4 0

2 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

$y = -16x^2 + 177x + 98$

It hits the ground when $y = 0$ , so we have to find x for which $y = 0$ , which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$y = -16x^2 + 177x + 98$

$-16x^2 + 177x + 98 = 0$

$a = -16, b = 177, c = 98$

$\bigtriangleup = 177^{2} - 4(-16)(98) = 37601$

$x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53$

$x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59$

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0

3 years ago

A garrison of 400men had food for 40days.After 10 days,200 more men joined them .How long will the food last now?(Assume that th

mestny [16]

Let $x$ be the amount of food needed for one man for one day. At the beginning, we have enough food for 400 men for 40 days, i.e.

$400\cdot 40\cdot x = 16000x$

After 10 days, the 400 men will have consumed

$400\cdot 10\cdot x = 4000x$

food, impliying that the food remaining is

$16000x-4000x=12000x$

If 200 more men join the garrison, there are now 600 men. Each of them requires $x$ food each day, and there are $12000x$ units of food remaining. They will last

$\dfrac{12000x}{600}=20$ days.

6 0

3 years ago