Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Answer:
Input is the value of w and the function f = 24/w as length x breadth = area of rectangle
If w = 0.5, then f = 24/0.5 = 48cm. So, it is a possible input of the function.
If w = 48, then f = 24/48 = 0.5cm. So, it is a possible input of the function.
If w = 0, then f = 24/0 = 0cm. So, it is not a possible input of the function as it cannot be defined
If w = -6, then f = 24/-6= -4cm. So, it is not a possible input of the function as a length and width can't be negative
If w = 3, then f = 24/3 = 8cm. So, it is a possible input of the function.
Answer:
AB + BC = AC Segment Addition Postulate
(x + 10) + (x + 14) = 22 Substitution
2x + 24 = 22 Simplify (added like terms)
2x = -2 Subtraction Property of Equality
x = -1 Divison Property of Equality
Answer: x = -1
Step-by-step explanation:
please give brainliest
<h2><em>I believe 10.91ft but I'm not sure.</em></h2>
Sqrt14 = 3.74165
smallest integer above = 4
