Is 104 and 12 hundreths greater than 104 and 2 hundreths

Ann [662]

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Question
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$\boxed { \frac{n+h}{5} = \frac{f+9}{9}}$

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Split the fraction on the left
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$\boxed { \frac{n}{5} + \frac{h}{5} = \frac{f + 9}{9}}$

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Take away h/5 from both sides
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$\boxed { \frac{n}{5} = \frac{f+9}{9} - \frac{h}{5}}$

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Change the denominator to be the same
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$\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}$

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Put it into single fraction
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$\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }$

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Rearrange (This step may not be necessary)
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$\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }$

$\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}$

6 0

3 years ago

Find the rate of change of total revenue, cost, and profit with respect to time. Assume that R(x) and C(x) are in dollars. R

tresset_1 [31]

Answer:

Step-by-step explanation:

Given the Total revenue R(x) = 2x

Cost C(x) = 0.01x²+0.3x+30 where;

x = 30 and dx/dt = 9units per day.

Rate of change of revenue dR/dt = dR/dx • dx/dt

dR/dt = 2dx/dt

dR/dt = 2(9) = $18

Rate of change of revenue with respect to time is 18dollars/day.

Rate of change of cost dC/dt = dC/dx • dx/dt

dC/dt = (0.02x+0.3)dx/dt

dC/dt at x = 30 and dx/dt = 9 will give;

dC/dt = {0.02(30)+0.3}×9

dC/dt = (0.6+0.3) × 9

dC/dt = 0.9×9

dC/dt = $8.1

Rate of change of cost with respect to time is 8.1dollars/day

Profit = Revenue - Cost

Profit = 18-8.1

Daily Profit = $9.9

4 0

3 years ago

Christian randomly selects students from his grade to rate a math test as easy, moderate, or difficult. Of the students he surve

IRINA_888 [86]

Answer:

84

Step-by-step explanation:

Total students he surveyed: 27

Amount that found it something OTHER than easy: 14 (11 moderate + 3 difficult)

This means that $\frac{14}{27}$ found it something other than easy

Multiply that by 162 to find the proportion for the larger population:

162 * (14/27), and we get 84.

4 0

2 years ago

How are the graphs of the function f(x)= square root 16^x and g(x)=3 square root 64^x related

34kurt

A is the correct awner

8 0

3 years ago

How much fencing does Farmer Gump need?

Agata [3.3K]

For the first field, he will need 40 m for the fence, this will cost £640 and he can have 10 sheep. For the second field, he will need 60 m for the fence, this will cost £960 and he can have 12 sheep.

<h3>What does this problem require?</h3>

This problem requires you to calculate the perimeter and area of each field and based on this information you can find the total of the fence the farmer requires, the cost, and the number of sheep.

<h3>How to calculate the perimeter?</h3>

You can calculate the perimeter by adding all the sides.

Field 1: 10m + 10m + 10m + 10m = 40 m
Field 2: 25m + 5m + 25m + 5m = 60 m

<h3>How to calculate the area?</h3>

To calculate the area, multiply the height by the width.

Field 1: 10 x 10 = 100m2
Field 2: 25 x 5 = 125m2

<h3>How much fencing does the farmer need?</h3>

The fencing needed is equal to the perimeter.

Field 1: 40 m of fencing
Field 2: 60 m of fencing

Multiply the number of meters needed by the price per meter ( £16 per meter).

Field 1: 40m x £16 per meter = £640
Field 2: 60 m x £16 per meter = £960

<h3>How many sheep can there be in each field?</h3>

To calculate this divide the area into the space required by each sheep (10m2).

Field 1: 100m2 / 10m2 = 10 sheep
Field 2: 125m2 /10m2 = 12 sheep

Note: This question is incomplete; here is the missing information:

Farmer Gump has two problems. His first problem is to work out how much fencing he needs to buy for his fields so his sheep don’t escape. His second problem is to work out how many sheep each field can hold—each sheep needs a minimum of 10m² of grass!

Sheep cost £65 each.

The fence is £16 per meter.

Learn more about perimeter in: brainly.com/question/6465134

4 0

3 years ago