Which of the following graphs represents logistic growth? NEED HELP ASAP!
1 answer:
You might be interested in
Answer:
Assume that all the coins involved here are fair coins.
a) Probability of finding the "odd" person in one round: .
b) Probability of finding the "odd" person in the th round:
.
c) Expected number of rounds: .
Step-by-step explanation:
<h3>a)</h3>To decide the "odd" person, either of the following must happen:
- There are
heads and
tail, or
- There are
Assume that the coins here all are all fair. In other words, each has a chance of landing on the head and a
The binomial distribution can model the outcome of coin-tosses. The chance of getting
heads out of
- The chance of getting
.
- The chance of getting
.
These two events are mutually-exclusive. would be the chance that either of them will occur. That's the same as the chance of determining the "odd" person in one round.
Since the coins here are all fair, the chance of determining the "odd" person would be in all rounds.
When the chance of getting a success in each round is the same, the geometric distribution would give the probability of getting the first success (that is, to find the "odd" person) in the
th round:
. That's the same as the probability of getting one success after
unsuccessful attempts.
In this case, . Therefore, the probability of succeeding on round
round would be
.
Let is the chance of success on each round in a geometric distribution. The expected value of that distribution would be
.
In this case, since , the expected value would be
.
Answer:
(a) The probability that both computers are ancient is 0.7396
(b) The probability that all seven computers are ancient is 0.3479
(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.
Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.
Step-by-step explanation:
We know that 86% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.
(a) To find the probability that two computers are chosen at random and both are ancient you must,
The probability that the first computer is ancient is and the probability that the second computer is ancient is
These events are independent; the selection of one computer does not affect the selection of another computer.
When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.
Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".
(b) To find the probability that seven computers are chosen at random and all are ancient you must,
Following the same logic in part (a) we have
Let A be the event "the first computer is ancient",
B the event "the second computer is ancient",
C the event "the third computer is ancient",
D the event "the fourth computer is ancient",
E the event "the fifth computer is ancient",
F the event "the sixth computer is ancient", and
G the event "the seventh computer is ancient"
(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge you must
Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.
Let C the event "the computer is cutting dash edge".
Let A the event "the seven computers are ancient".
Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.