We have the parabola with equation y = 4x².
We have to determine the shape and direction of it.
If we compare it to the standard equation y = ax² + bx + c, we can see that a = 4, b = 0 and c = 0.
As the value of a is positive, the parabola will open upward.
The parameter has an absolute value greater than 1. This means that y increases "faster" relative to x that a parabola with a = 1.
This means that the parabola will be narrow about its line of symmetry which we call vertical strecth.
Answer:
Because a is positive the parabola opens upward.
Because a has an absolute value larger than 1 the parabola is narrow about its line of symmetry which we call vertical stretch.
The answer is: " <span>3x² − 17 " .
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f(x) = 3x + 1 ;
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If g(x) = x² − 6 ;
then: (f o g)(x) = f(x² − 6) = 3x + 1 ;
= 3(x² − 6) + 1 = 3x² − 18 + 1 ;
= 3x² − 17 .
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Answer:

Step-by-step explanation:

Here cross - multiplying 3 & 2 gives :-

Solving this further gives :-

Answer:
A
Step-by-step explanation:
Time Distance
0 0
2 2*25 = 50
4 4*25 = 100
6 6*25= 150
8 8 * 25 = 200