When writing a decimal, the numbers to the left of the decimal are whole numbers greater then or equal to 1. The numbers to the right of the decimal are numbers less then 1.
if u know 5/8 = 0.625, then 4 5/8 = 4.625
So you just need to use the crocodile signs < or >
As j is less than 113 we put j on the smaller side and 113 on the bigger side to make:
j<113
The answer would be D.
you would start by choosing one of the variables to eliminate, i chose to eliminate X first. in order to eliminate X, i had to multiply the second equation by -2. X then cancelled out, and i solved for the Y the same way you would a 1 step equation. Y=-4
I then took the first original equations, plugged Y in, and solved for X. X=3.
Hope this helps!
Answer:
It takes 4 one-sixth sized pieces to make the two-thirds. and we can see that there 1 \times 6 = 6 sixths in a whole.
Step-by-step explanation:
Consider a circle with radius 
centered at some point 
on the 
-axis. This circle has equation
Revolve the region bounded by this circle across the 
-axis to get a torus. Using the shell method, the volume of the resulting torus is
where 
.
So the volume is
Substitute
and the integral becomes
Notice that 
is an odd function, so the integral over ![\left[-\frac\pi2,\frac\pi2\right]](https://tex.z-dn.net/?f=%5Cleft%5B-%5Cfrac%5Cpi2%2C%5Cfrac%5Cpi2%5Cright%5D)
is 0. This leaves us with
Write
so the volume is
