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erastovalidia [21]
1 year ago
8

16. Solve for "x". a. 6 b. 100 c. 36

Mathematics
1 answer:
erastovalidia [21]1 year ago
5 0

Answer:

A. 6

Step-by-step explanation:

Using the Pythagorean theorem which states that: <u>Hypotenus² = Opposite² + Adjacent²</u>

Where: hypotenus = 10, opposite = x, adjacent = 8

So:

{10}^{2}  =  {x}^{2}  +  {8}^{2}

Solving for x

100 =  {x}^{2}  + 64

Collect like terms to make x the subject of formula

100 - 64 =  {x}^{2} →36 =  {x}^{2}

36 =  {x}^{2} ⟹ {x}^{2}  = 36

square root both sides of the equation to find the value of x

\sqrt{ {x}^{2} }  =  \sqrt{36} →x = 6

Therefore: Option A is correct

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Which graph is NOT a function?
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Step-by-step explanation:

Use the vertical line test to determine whether or not a graph represents a function. If a vertical line is moved across the graph and, at any time, touches the graph at only one point, then the graph is a function. If the vertical line touches the graph at more than one point, then the graph is not a function.

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A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.

b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.

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3 years ago
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6. Marcus sold 6 pizzas. Sue sold 4 pizzas.
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Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

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