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1 year ago

16. Solve for "x". a. 6 b. 100 c. 36

Mathematics

1 answer:

erastovalidia [21]1 year ago

5 0

Answer:

A. 6

Step-by-step explanation:

Using the Pythagorean theorem which states that: Hypotenus² = Opposite² + Adjacent²

Where: hypotenus = 10, opposite = x, adjacent = 8

So:

${10}^{2} = {x}^{2} + {8}^{2}$

Solving for x

$100 = {x}^{2} + 64$

Collect like terms to make x the subject of formula

$100 - 64 = {x}^{2} →36 = {x}^{2}$

$36 = {x}^{2} ⟹ {x}^{2} = 36$

square root both sides of the equation to find the value of x

$\sqrt{ {x}^{2} } = \sqrt{36} →x = 6$

Therefore: Option A is correct

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Pls help me on this question:)

r-ruslan [8.4K]

Answer:

x= 28

Step-by-step explanation:

The angles both sum up to 180°. So, the equation would be: 39+(5x+1)= 180.

Step 1- Add common numbers.

(39+1)+5x= 180

40+5x= 180

Step 2- Subtract 40 to both sides.

40+5x= 180

-40 -40

5x= 140

Step 3- Divide both sides by 5.

5x= 140

5 5

x= 28

5 0

3 years ago

Mr.Williams physical education class lasts 7/8 hour if instruciton is 1/5 how many minutes are not spent on instruction?

34kurt

= 7/8 − 1/5

= ((7 × 5) − (1 × 8)) / (8 × 5)

= (35 - 8) / 40

= 27/40

= 27/40

SO, 27/40 minutes are NOT spend on instructions.

Hope I helped:P

8 0

2 years ago

Read 2 more answers

Can anyone help me please.

Delvig [45]

How am I suppose to help you if I can’t see the words. It’s too blurry.

3 0

3 years ago

What is 2xy-3yz+5+2yz-xy

melomori [17]

To simplify this expression, we are going to combine like terms.

First, we can see that we have two terms with the variables $xy$ being multiplied together, $2xy$ and $-xy$ . Together, these add to $xy$ , so our expression is now:

$xy - 3yz + 5 + 2yz$

We also have two terms with $yz$ , $-3yz$ and $2yz$ . Together, these add to $-yz$ , so our expression is now:

$xy - yz + 5$

Our final expression is xy - yz + 5.

6 0

2 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: