(x+a)^4 = ^4C_0 x^4 + ^4C_1 x^{4-1} a + ^4C_2x^{4-2}a^2 + ^4C_3x^{4-3}a^3 + ^4C_4x^{4-4}a^4
= x^4 + 4x^3a + 6x^2a^2 + 4xa^3 + a^4
Answer:
see below
Step-by-step explanation:
We can just add up all of these fractions:
2 1/8 + 7/8 = 2 8/8 = 3
8 5/8 + 4/8 = 8 9/8 = 9 1/8
3 + 9 1/8 = 
because 1+1+1+1=4 and thats 4 1's 1+1=2 2+2=4
6[13-2(4+1)]
Solve what is in the bracket first.
Parenthesis first.
6[13-8-2]
6(3)
18
The possibilities of an even number are 2, 4, 6, 8, 10, 12, 14, and 16 .
The possibilities of an odd prime are 3, 5, 7, 11, and 13.
8 even numbers + 5 odd primes = 13 possibilities of success
out of 16 total possible outcomes.
Probability of success = 13/16 = 0.8125 = 81.25% .
Rounded to the nearest thousandth, it's 0.813 .