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lilavasa [31]
1 year ago
3

Suppose that the functions and are defined for all real numbers as follows.

Mathematics
1 answer:
Mademuasel [1]1 year ago
7 0

The expression we get from the given functions f and g defined for all real numbers x.

(f+g)(x)=4x+1

(f-g)(x)=2x+11

(f.g)(3)=-30

Given that,

All real numbers x are defined by the functions f and g.

f(x)=3x+6

g(x)=x-5

We have to find the expression

(f+g)(x), (f-g)(x) and (f.g)(3)

Take the functions,

f(x)=3x+6

g(x)=x-5

Now, First

(f+g)(x)

f(x)+g(x)           (Substitute in the place of f and g functions)

Which is

3x+6+x-5

4x+1

(f+g)(x)=4x+1

Now, second

(f-g)(x)

f(x)-g(x)

Which is

3x+6-(x-5)

3x+6-x+5

2x+11

(f-g)(x)=2x+11

Now, third

(f.g)(3)

f(3)×g(3)

Which is

(3(3)+6)×((3)-5)

(9+6)×(3-5)

15×-2

-30

(f.g)(3)=-30

Therefore, The expression we get from the given functions f and g defined for all real numbers x.

(f+g)(x)=4x+1

(f-g)(x)=2x+11

(f.g)(3)=-30

To learn more about expression visit: brainly.com/question/14083225

#SPJ1

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Answer:

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Step-by-step explanation:

If a equation has two zeros x=a and x=b then equation can be written as

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similarly if a equation has two zeros at x = −6 and x = 2

then equation can be written as

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Help please! (Explanations are preferred, since I have to know how to do this for a test)
Galina-37 [17]
Which one do you need help with 


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3 years ago
How do I solve this?
vodomira [7]
I’m assuming what you’re asking here is how to *factor* this expression. For that, let’s rearrange the expression into a more familiar form:

-c^2-4c+21

From here, we’ll factor out a -1 so that we have:

-(c^2+4c-21)

Let’s focus on the quadratic expression inside the parentheses. To find our factors (c + x)(c + y), we’ll need to find two terms x and y that multiply together to make -21 and add together to make 4. It turns out that the numbers -3 and 7 work out perfectly for that purpose (-3 x 7 = -21 and 7 + (-3) = 4), so substituting them in for x and y, we have:

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And adding back on the negative from a few steps earlier:

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7 0
3 years ago
The midpoint of GH is M(3, 0). One endpoint is G(1, 0). Find the coordinates of the other endpoint H.
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