Help please! (Explanations are preferred, since I have to know how to do this for a test)

Mathematics

1 answer:

Galina-37 [17]3 years ago

3 0

Which one do you need help with

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PLEASE HELP ASAPP WRONG ANSWERS GET REPORTED GOOD ANSWERS GET BRAINLIEST, THANK YOU :)

Helen [10]

(9) The correct Option is (C) 4, -3

Explanation:
The left hand limit is:
$\lim_{x \to 2^-} f(x) = +4$

+4 because the line(y=+4) is constant if limit approaches to 2 (from left side of the graph)

The right hand limit is:
$\lim_{x \to 2^+} f(x) = -3$

-3 because the line(y=-3) is constant if limit approaches to 2 (from the right side of the graph)

So the correct Option is (C) 4, -3

(10) The correct Option is (C) -4

Explanation:
$\lim_{x \to 3^+} f(x) = -4$

The plus sign in the limit indicates that it is the right hand limit. So we have to approach to 3 from the right side of the graph. When we do that, we see the constant line y = -4. Hence the correct option is (C)

NOTE: Although the question seems complex because there is slope involved but in this particular case, the examiner is concerned about the right hand limit. If she or he asks the left hand limit(3-minus) then we would take the slope-line.

P.S. Sorry for bit late reply! I thought somebody answered it already! :)

7 0

3 years ago

Fiona loves pizza. She ate of a pizza for dinner one night. She ordered another pizza the

kvv77 [185]

$\stackrel{1st~night}{\cfrac{5}{6}}+\stackrel{\textit{2nd night}}{\cfrac{1}{3} }\implies \cfrac{(1)5~~ +~~(2)1}{\underset{\textit{using this LCD}}{6}}\implies \cfrac{7}{6}\implies 1\frac{1}{6}$