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WITCHER [35]
1 year ago
14

Find the derivative of 3e^y+x=y

Mathematics
1 answer:
Sindrei [870]1 year ago
4 0

You have the following function:

y=3e^y+x

Derivate implictly the previous expression, as follow:

y^{\prime}=3e^yy^{\prime}+1

Where you have used that:

(e^y)^{\prime}=e^yy^{\prime}

Then, the implicit derivative of the given expression is:

y^{\prime}=3e^yy^{\prime}+1

Next, solve for y' as follow:

\begin{gathered} y^{\prime}-3e^yy^{\prime}=1 \\ (1-3e^y)y^{\prime}=1 \\ y^{\prime}=\frac{1}{1-3e^y} \end{gathered}

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