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xxMikexx [17]
3 years ago
8

How to Break apart 3x7

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
Well brake 7 into 5 and 2 and then  just multiply it by 3 so it would be 5 x3=15 and 2x3=6 then u add 15+6 it would be the sum, of 21 so 3x7=21
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Factorise a.x3+4.a.x​
Contact [7]

Answer:

{ax}^{3}  + 4ax \\

factorise out a and x :

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but from general factorization:

{ \boxed{( {a}^{2} +  {b}^{2}) =  {(a + b)}^{2}   - 2ab }}

a » x

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therefore:

= ax \{ {(x + 2)}^{2}  - 2(x)(2) \} \\  \\  = { \boxed{ \boxed{ax( {x + 2)}^{2} - 4x }}}

4 0
3 years ago
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lianna [129]
In order to solve for a nth term in an arithmetic sequence, we use the formula written as:<span>

an = a1 + (n-1)d

where an is the nth term, a1 is the first value in the sequence, n is the term position and d is the common difference.

First, we need to calculate for d from the given values above.  
<span>a3 = 20.5 and a8 = 13
</span>

an = a1 + (n-1)d
20.5 = a1 + (3-1)d

</span>an = a1 + (n-1)d
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<span>
a1 = 23.5
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The 11th term is calculated as follows:

a11 = a1 + (n-1)d
a11= 23.5 + (11-1)(-1.5)
a11 = 8.5</span>
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The answer is 140 percent
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Alexxx [7]

Answer:

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Step-by-step explanation:

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3 years ago
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