Question

What is the area of this trapezoid? Enter your answer in the box. Cm² Trapezoid with top base length of 14 centimeters, bottom base length of 28 centimeters, and a height of 16 centimeters

Answer 1

Answer: 336 square centimeters.

Step-by-step explanation:

We know that the area of the trapezoid is given by :-

$A=\dfrac{1}{2}h(a+b)$ , where a and b are the measure of opposite parallel sides and h is height.

Given : a = 14 cm   ; b= 28 cm    h= 16

Then, the area of the trapezoid will be :-

$A=\dfrac{1}{2}(16)(14+28)\\\\=8\times42=336\ cm^2$

Hence, the area of trapezoid = 336 square centimeters.

Answer 2

Answer: 336 cm²

Step-by-step explanation:

A trapezoid looks like a rectangle with 2 traingles attached to the side, yeah? So imagine cutting off those 2 triangles. In the middle you have a rectangle with the dimensions of 14 cm by 16 cm. The area of that rectagle is 224 cm². By subtracting the top base length from the bottom base length, you get the length of the two triangles. So, it would be 28 cm - 14 cm, giving you 14 cm. There were 2 triangles, so cut that length in half and you get 7 cm for the base of one traingle. To find the area of 1 traingle, you would do 1/2 multiplied by 7 multiplied by 16. But you have 2 triangles. so the 1/2 step isn't needed because if you put the two triangles together, you get a new rectangle. Thus, when you add the area of this new rectangle, you get 112 cm². Add this to the original rectangle, and your final area is 336 cm².