Answer:
The correct answer is - through facilitated diffusion and active transport.
Explanation:
Glucose is a six-carbon sugar molecule that is directly utilized by cells to provide energy. A glucose molecule is large enough to go through a cell membrane with simple diffusion.
Cells help glucose molecules to cross the cell membrane through facilitated diffusion and active transport. Active transport is of two types primary and secondary active transport to help the glucose molecule to cross the membrane.
Thus, the correct answer is - through facilitated diffusion and active transport.
The correct answer is A) A roast at 125°F (52°C)
Explanation:
In general terms, bacteria thrive at warm temperatures; this means bacterial growth is lower at extremely hot/cold temperatures, but it is higher at warm or medium temperatures. Indeed, the ideal temperature for bacteria to develop and reproduce is between 4° C and 60°C. This implies from the options given the roast at 52°C represents an ideal temperature for the growth of bacteria. Also, other options include temperatures above 60°C, and therefore do not allow bacteria to grow well.
Answer:
To prepare a proper seed bed.
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