Answer:
c. 61.25 kg
Step-by-step explanation:
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.
a. 15.31 kg
b. 51.40 kg
c. 61.25 kg
d. 80.49 kg
Margin of Error Formula= z × Standard deviation/√n
95% confidence interval = 1.96
Standard deviation = 125kg
n = 16 samples
Margin of error= 1.96 × 125/√16
= 1.96 × 125/4
= 245/4
= 61.25kg
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg
"At most 12" means "the highest we can go is 12". Think of it as the ceiling. So x can equal 12 or it can be smaller. This means 
<h3>Answer: Choice A</h3>
Answer:
262.5
Step-by-step explanation:
35 percent * 750 =
(35:100)* 750 =
(35* 750):100 =
26250:100 = 262.5
4g/cm^3
D = M/V
100g/25cm^3 = 4g/cm^3
Answer:
203.46$
Step-by-step explanation:
Its simple, do it like a simple minus problem, 26189-5218-625=20346, or in this case, 203.46$
