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1 year ago

Match each expression to the correct point

Mathematics

1 answer:

ziro4ka [17]1 year ago

3 0

Using number line and mental mathematics, the value of u = -√25, t = - 2π, s = -√68

<h3>What is a number line?</h3>

A horizontal line with evenly spaced numerical increments is referred to as a number line. How the number on the line can be answered depends on the numbers present.

The usage of the number is determined by the question that it corresponds to, such as when graphing a point.

As we can observe that

All the points lie on negative axis. The value of u = -√25 = 5

t = -2π = -2×3.14 = -6.28

s = -√68 = - 8.24

To learn more about number line from given link

brainly.com/question/22667895

#SPJ9

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Help me please thanks in advance

Xelga [282]

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From up to down ;

_________________________________

The first box :

$f(n) = 3. ({2})^{n - 1}$

The second box :

$f(n) = 2. ({4})^{n - 1}$

The third box :

$f(n) = 2. ({6})^{n - 1}$

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4 0

3 years ago

Find the values of the variables for which ABCD must be a parallelogram

sleet_krkn [62]

Answer:

y=5 and x=4

Step-by-step explanation:

So,the diagonals of a parallelogram bisect each other..

therefore,we have our two eqn

4x-2=3y-1------------(i)

3y-3=3x

or,y-1=x----------(ii)

Now,simply substitute value of x in eqn (i)

4(y-1)-2=3y-1

or,4y-4-2=3y-1

or,y=5

Again,substitute y=5 in eqn (ii)

5-1=x

therefore,

x=5

Hope it helps you!!!

4 0

4 years ago

Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid

Gnom [1K]

Answer:

The area of the triangle is $A=\sqrt{\frac{4027}{2}}$

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

$A=\frac{1}{2}||{\bf u} \times {\bf v} ||$

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

${\bf AB}$ and ${\bf AC}$

The vector ${\bf AB}$ is the difference of point B minus point A

${\bf AB}=(5-3,5-5,0-9)=(2,0,-9)$

and the vector ${\bf AC}$ is the difference of point C minus point A

${\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)$

Next we need to find the cross product of this vectors.

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

This is the definition of cross product of two vectors in space:

Let ${\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k}$ and ${\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k}$ be vectors in space. The cross product of ${\bf u}$ and ${\bf v}$ is the vector

${\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}$

Applying this definition we get

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

$\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}$

$||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}$

The area of the triangle is

$A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}$

7 0

4 years ago

John is arguing that they should use the following expressions to calculate the final cost of this item: (20-20•0.15)+(20-20•0.1

Vikki [24]

If they use (20-20x0.15)+(20-20x.015)x0.05 the final cost would be $34.05

Hope this helps

3 0

4 years ago

Slope between two points 12,6 and 20,22

pogonyaev

<span>Here's the official formula:
If you have two points :
L(a,b) and M(c,d)
slope=(d-b)/(c-a)
We have:
M(20,22) and L(12,6)
slope=(22-6)/(20-12)=16/8=2</span>

7 0

3 years ago