Please help!!! A. (2,-22) b. (-8,-64) c. (7,-1) d.(-6,2/7)

Please please help. The table list the heights of four trees, Sycamore 15 and 2/3, Oak 14 and 3/4, Maple 15 and 3/4, Birch 15.72

ladessa [460]

Sycamore=15.6 recurring
Oak=14.75
Maple=15.75
Birch=15.72
Therefore, A and B are true

6 0

3 years ago

If you help me answer this question i will give you brainiest!!

coldgirl [10]

Angle BDC is given as 38° but not drawn in the figure. Amateurs.

We calculate angle DBC

DBC = 180° - 96° - 38° = 180° - 134°

We won't bother subtracting because we're really after

angle ABD = 180° - DBC = 134°

Now we have a Law of Cosines situation,

AD² = AB² + BD² - 2(AB)(BD) cos ABD

AD = √( 5.8² + 27.3² - 2(5.8)(27.3) cos 134°)

AD ≈ 31.61 m

Answer: 31.6 m

5 0

3 years ago

Read 2 more answers

Find the area of the shaded region

Dimas [21]

The area of the shaded region is 15.453 square units.

Step-by-step explanation:

Step 1:

The given shape consists of a rectangle and two circles.

The length of the rectangle is given as 12 cm. Both the diameters of the circles equal 12 cm. So each circle has a diameter of 6 cm and thus a radius of 3 cm.

The diameter of the circle is equal to the width of the rectangle.

So the rectangle has a length of 12 cm and a width of 6 cm. The circles have radii of 3 cm each.

Step 2:

The area of the rectangle $= (l)(w) = (12)(6) = 72$ square cm.

The area of each circle $= \pi r^{2} = (3.1415)(3^{2} ) = 28.2735$ square cm.

The area of both circles $=2(28.2735) = 56.547$ square cm.

The area of the shaded region is the difference between the area of the rectangle and the area of both circles.

The area of the shaded region $= 72 - 56.547 = 15.453$ square units.

The area of the shaded region is 15.453 square units.

6 0

2 years ago

The current (I) varies directly as the voltage (V) in an electric circuit. If the current is 4 amperes when the voltage is 100 v

Margarita [4]

$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&& y={{ k }}x
\end{array}\\\\
-----------------------------\\\\$

$\bf \textit{l varies directly to V}\implies l=kV
\\\\\\
\textit{now, we also know that }
\begin{cases}
l=4\\
V=100
\end{cases}\implies 4=k100
\\\\\\
\cfrac{4}{100}=k\implies \cfrac{1}{25}=k\impliedby \textit{constant of variation}
\\\\\\
thus\implies l=\cfrac{1}{25}V
\\\\\\
\textit{what is the current when the voltage is 75?}\qquad l=\cfrac{1}{25}\cdot 75$

6 0

3 years ago

[(-7)+9]+(______)=9+[-7+4]<br><br>Fill in the blanks

Katen [24]

Answer:

[(-7)+9]+(+4)=9+[-7+4]

5 0

2 years ago