Answer:
A. 6x^3 - 24x^2 + 6x + 36.
Step-by-step explanation:
(2x - 6)(3x^2 - 3x - 6)
= 2x(3x^2 - 3x - 6) - 6(3x^2-3x-6)
= 6x^3 - 6x^2 - 12x - 18x^2 + 18x + 36
Simplifying like terms:
= 6x^3 - 24x^2 + 6x + 36 (answer).
Answer:
120/5
24 inches.
Step-by-step explanation:
The formula to solve for thee area of a square pyramid is [ V = 1/3 * b² * h ]
b² = base area (b = length of one side of the base)
h = height
The only option that as a base length of 12cm. and a height of 14cm. is the first option.
Solve for the volume if needed.
V = 1/3(12²)(14)
V = 1/3(144)(14)
V = 1/3(2,016)
V = 672cm²
Best of Luck!
All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.
2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30
3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents
4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
9514 1404 393
Answer:
(0, 2), (5, 5)
Step-by-step explanation:
The w-intercept is the constant in the equation, so you know immediately that (x, w) = (0, 2) is one point on your graph.
Since the value of x is being multiplied by 3/5, it is convenient to choose an x-value that is a multiple of 5. When x=5, we have ...
w(5) = (3/5)(5) +2 = 3+2 = 5
So, (x, w) = (5, 5) is another point on your graph.
