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1 year ago

What are 2 common mistakes people make when using quotient rule with exponents?

Mathematics

1 answer:

NemiM [27]1 year ago

5 0

Answer:

1. Not accounting for the difference in the base of the exponent when applying the quotient rule.

2. Not subtracting the exponents of the denominator from the exponent of the numerator when applying the quotient rule.

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The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde

Akimi4 [234]

we are given

quadratic equation as

$3x^2-4x+15=0$

now, we can find b and c from

$x^2+bx+c=0$

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

$3x^2-4x+15=0$

$\frac{3x^2-4x+15}{3}= \frac{0}{3}$

$\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}$

now, we can simplify it

$x^2-\frac{4}{3}x+5= 0$

now, we can compare it with

$x^2+bx+c=0$

we get

$b=-\frac{4}{3}$

$c=5$

so, we get order pair as

$(b,c)=(-\frac{4}{3} , 5)$ ..............Answer

6 0

3 years ago

Read 2 more answers

Write rational number in number line -7 upon 2

Leno4ka [110]

Answer:

el numero 1

Step-by-step explanation:

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3 years ago

I'll give 100 brainly points, i just need help...plz

Solnce55 [7]

Answer:

A. $(x^{2/7})(y^{-3/5})$

Step-by-step explanation:

The numerator is:

$\sqrt[7]{x^2} = (x^2)^{1/7} = x^{2/7}\\$

The denominator is:

$\sqrt[5]{y^3} = (y^3)^{1/5} = y^{3/5}$

The fraction is equivalent to:

$\frac{x^{2/7}}{y^{3/5}} =$
$(x^{2/7})(y^{-3/5})$

Correct choice is A

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Elanso [62]

Answer:

Step-by-step explanation:

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3 years ago

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80/200. is the probability

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3 years ago