Step-by-step explanation:

Multiply both numerator and denominator by 100. We do this to find an equivalent fraction having 100 as the denominator.

Multiply both numerator and denominator by 100. We do this to find an equivalent fraction having 100 as the denominator.

= (1.172 × 100) × 1/100=117.2/100

Write in percentage notation: 117.2%

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3 years ago

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Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int

meriva

Answer:

b) 95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14

sample standard deviation 'S' = 9.3

95 percent confidence interval for this single-sample t test

The values are $(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })$ the 95 percent confidence interval for the population mean 'μ'

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

$(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })$

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

Conclusion:-

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

6 0

3 years ago

It takes an average of 22 weeks for someone over 55 to find a new job, compared with 16 weeks for younger workers. assume the pr

Mademuasel [1]

(a) someone over 55
mean, mu = 22
standard deviation, sigma = 2
X=19
Z(X)=(X-mu)/sigma=(19-22)/2=-1.5
P(x>X)=1-P(x<X)=1-0.0668072=0.9331928
Therefore probability for a 55-year old to find a job in over 19 weeks is 0.9332

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3 years ago

What is the area of 5ft 4ft 5ft 6ft

defon

The area of 5ft, 4ft, 5ft, 6ft, is 50 ft.

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3 years ago

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