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1 year ago

Needed help asap please and thank you so much !

Mathematics

1 answer:

Novosadov [1.4K]1 year ago

8 0

Step-by-step explanation:

based on the story told I expected completely different questions.

but for the actually asked question the whole thing about gaining our not gaining weight is competent irrelevant. ignore it.

so, all we need to do is looking at the row totals.

27.4% of the participants took 1 vitamin.

49.5% of the participants took more than 1 vitamin.

so, 49.5% + 27.4% = 76.9% of all participants are taking vitamins in some form.

therefore, the second answer option is correct.

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Help me out on this please I sent an image down below

abruzzese [7]

60 degrees because vertical angles are congruent if you move line y 5 degrees clockwise then you are adding 5+55=60 and since 1 and 3are congruent 3=60 degrees

3 0

3 years ago

Which expression represents the quotient of the model shown? -x2 O x + 3 x - 3 lolo o O -X-3 -x + 3

Bess [88]

Answer:

Step-by-step explanation:

Given the expression

-x^2 + x + 3 x - 3

Factorize

(-x^2 + x) + (3 x - 3)

-x(x-1)+3(x-1)

= (x-1)(-x+3)

Hence one of the quotient is -x+3

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3 years ago

What is the explicit rule for this geometric sequence? a1=-15;an=1/5•an-1

Ad libitum [116K]

Answer:

Option A is correct.

$a_n =-15 (\frac{1}{5})^{n-1}$

Step-by-step explanation:

Given: $a_1 = -15$ ; $a_n = \frac{1}{5} \cdot a_{n-1}$

for n = 2

$a_2 = \frac{1}{5} \cdot a_{2-1}$ = $\frac{1}{5}\cdot a_1 = \frac{1}{5} \cdot (-15)$

for n =3

$a_3 = \frac{1}{5} \cdot a_{3-1}$ = $\frac{1}{5} \cdota_2= (\frac{1}{5})^2\cdot (-15)$

Simlarly , for n =4

$a_3 = \frac{1}{5} \cdot a_{4-1}$ = $\frac{1}{5}\cdot a_3= (\frac{1}{5})^3\cdot (-15)$

and so on...

Common ratio(r) states that for a geometric sequence or geometric series, the common ratio is the ratio of a term to the previous term.

we have; $r = \frac{a_2}{a_1} = \frac{1}{5}$

Now; by recursive formula for geometric series:

$a_n = a_1 r^{n-1}$

where $a_1$ is the first term and r is the common ratio:

Substitute the value of $a_1 = -15$ and $r = \frac{1}{5}$

we have;

$a_n =-15 (\frac{1}{5})^{n-1}$

therefore, the explicit rule for the geometric sequence is; $a_n =-15 (\frac{1}{5})^{n-1}$

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3 years ago

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Answer:

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Step-by-step explanation:

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